| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.03 |
| Score | 0% | 61% |
Damon loaned Roger $500 at an annual interest rate of 1%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $8 | |
| $5 | |
| $56 | |
| $36 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $500
i = 0.01 x $500
i = $5
Solve 4 + (3 + 2) ÷ 4 x 2 - 42
| -9\(\frac{1}{2}\) | |
| 1\(\frac{1}{5}\) | |
| \(\frac{3}{5}\) | |
| 1 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (3 + 2) ÷ 4 x 2 - 42
P: 4 + (5) ÷ 4 x 2 - 42
E: 4 + 5 ÷ 4 x 2 - 16
MD: 4 + \( \frac{5}{4} \) x 2 - 16
MD: 4 + \( \frac{10}{4} \) - 16
AS: \( \frac{16}{4} \) + \( \frac{10}{4} \) - 16
AS: \( \frac{26}{4} \) - 16
AS: \( \frac{26 - 64}{4} \)
\( \frac{-38}{4} \)
-9\(\frac{1}{2}\)
What is \( \frac{-2z^7}{3z^3} \)?
| -\(\frac{2}{3}\)z\(\frac{3}{7}\) | |
| -\(\frac{2}{3}\)z10 | |
| -\(\frac{2}{3}\)z4 | |
| -\(\frac{2}{3}\)z2\(\frac{1}{3}\) |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-2z^7}{3z^3} \)
\( \frac{-2}{3} \) z(7 - 3)
-\(\frac{2}{3}\)z4
On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 60% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 15 | |
| 23 | |
| 28 | |
| 36 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{60}{100} \) = \( \frac{60 x 15}{100} \) = \( \frac{900}{100} \) = 9 shots
The center makes 40% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{9}{\frac{40}{100}} \) = 9 x \( \frac{100}{40} \) = \( \frac{9 x 100}{40} \) = \( \frac{900}{40} \) = 23 shots
to make the same number of shots as the guard and thus score the same number of points.
What is 2c3 x 2c5?
| 4c8 | |
| 4c5 | |
| 4c-2 | |
| 4c15 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
2c3 x 2c5
(2 x 2)c(3 + 5)
4c8