To add these radicals together their radicands must be the same:

9\( \sqrt{28} \) + 2\( \sqrt{7} \)
9\( \sqrt{4 \times 7} \) + 2\( \sqrt{7} \)
9\( \sqrt{2^2 \times 7} \) + 2\( \sqrt{7} \)
(9)(2)\( \sqrt{7} \) + 2\( \sqrt{7} \)
18\( \sqrt{7} \) + 2\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

First, solve for \( \left|y - 2\right| \):

\( \left|y - 2\right| \) + 0 = 1
\( \left|y - 2\right| \) = 1 + 0
\( \left|y - 2\right| \) = 1

The value inside the absolute value brackets can be either positive or negative so (y - 2) must equal + 1 or -1 for \( \left|y - 2\right| \) to equal 1:

So, y = 1 or y = 3.

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{44}{7} \) = 6\(\frac{2}{7}\)

So, it will take 6 full vans and one partially full van to transport the entire team making a total of 7 vans.

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{8} \) x \( \frac{2}{7} \) = \( \frac{3 x 2}{8 x 7} \) = \( \frac{6}{56} \) = \(\frac{3}{28}\)

To divide fractions, invert the second fraction and then multiply:

\( \frac{1}{6} \) ÷ \( \frac{4}{9} \) = \( \frac{1}{6} \) x \( \frac{9}{4} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{6} \) x \( \frac{9}{4} \) = \( \frac{1 x 9}{6 x 4} \) = \( \frac{9}{24} \) = \(\frac{3}{8}\)