| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.49 |
| Score | 0% | 70% |
Simplify \( \frac{28}{52} \).
| \( \frac{7}{13} \) | |
| \( \frac{4}{19} \) | |
| \( \frac{5}{17} \) | |
| \( \frac{5}{19} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{28}{52} \) = \( \frac{\frac{28}{4}}{\frac{52}{4}} \) = \( \frac{7}{13} \)
What is -9b3 + 4b3?
| -5b6 | |
| -5b3 | |
| -13b3 | |
| 13b-3 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-9b3 + 4b3
(-9 + 4)b3
-5b3
17 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?
| 9 | |
| 4 | |
| 8 | |
| 5 |
There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 17 people needing transportation leaving 17 - 12 = 5 who will have to find other transportation.
How many 2 gallon cans worth of fuel would you need to pour into an empty 20 gallon tank to fill it exactly halfway?
| 3 | |
| 5 | |
| 6 | |
| 5 |
To fill a 20 gallon tank exactly halfway you'll need 10 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{10 \text{ gallons}}{2 \text{ gallons}} \) = 5
What is the greatest common factor of 16 and 28?
| 4 | |
| 12 | |
| 6 | |
| 15 |
The factors of 16 are [1, 2, 4, 8, 16] and the factors of 28 are [1, 2, 4, 7, 14, 28]. They share 3 factors [1, 2, 4] making 4 the greatest factor 16 and 28 have in common.