ASVAB Arithmetic Reasoning Practice Test 352261 Results

Your Results Global Average
Questions 5 5
Correct 0 3.36
Score 0% 67%

Review

1

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

integer

fraction

mixed number

improper fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


2

What is \( \frac{3}{5} \) ÷ \( \frac{1}{8} \)?

68% Answer Correctly
\(\frac{1}{21}\)
\(\frac{1}{12}\)
4\(\frac{4}{5}\)
24

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{3}{5} \) ÷ \( \frac{1}{8} \) = \( \frac{3}{5} \) x \( \frac{8}{1} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{5} \) x \( \frac{8}{1} \) = \( \frac{3 x 8}{5 x 1} \) = \( \frac{24}{5} \) = 4\(\frac{4}{5}\)


3

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for multiplication

distributive property for division

commutative property for division

commutative property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


4

A triathlon course includes a 300m swim, a 40.7km bike ride, and a 12.3km run. What is the total length of the race course?

69% Answer Correctly
53.3km
35.8km
37.3km
26.6km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 300 meters to kilometers, divide the distance by 1000 to get 0.3km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.3km + 40.7km + 12.3km
total distance = 53.3km


5

In a class of 23 students, 11 are taking German and 10 are taking Spanish. Of the students studying German or Spanish, 5 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
7
15
13
20

Solution

The number of students taking German or Spanish is 11 + 10 = 21. Of that group of 21, 5 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 21 - 5 = 16 who are taking at least one language. 23 - 16 = 7 students who are not taking either language.