ASVAB Arithmetic Reasoning Practice Test 352856 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

Which of the following is not an integer?

77% Answer Correctly

-1

0

1

\({1 \over 2}\)


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


2

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

least common factor

absolute value

greatest common factor

least common multiple


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


3

What is \( \frac{-5y^6}{2y^2} \)?

60% Answer Correctly
-2\(\frac{1}{2}\)y12
-2\(\frac{1}{2}\)y4
-2\(\frac{1}{2}\)y3
-\(\frac{2}{5}\)y4

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-5y^6}{2y^2} \)
\( \frac{-5}{2} \) y(6 - 2)
-2\(\frac{1}{2}\)y4


4

If \( \left|y + 3\right| \) - 5 = 3, which of these is a possible value for y?

62% Answer Correctly
-9
5
4
14

Solution

First, solve for \( \left|y + 3\right| \):

\( \left|y + 3\right| \) - 5 = 3
\( \left|y + 3\right| \) = 3 + 5
\( \left|y + 3\right| \) = 8

The value inside the absolute value brackets can be either positive or negative so (y + 3) must equal + 8 or -8 for \( \left|y + 3\right| \) to equal 8:

y + 3 = 8
y = 8 - 3
y = 5
y + 3 = -8
y = -8 - 3
y = -11

So, y = -11 or y = 5.


5

What is \( 4 \)\( \sqrt{32} \) + \( 9 \)\( \sqrt{2} \)

35% Answer Correctly
25\( \sqrt{2} \)
13\( \sqrt{64} \)
13\( \sqrt{32} \)
13\( \sqrt{16} \)

Solution

To add these radicals together their radicands must be the same:

4\( \sqrt{32} \) + 9\( \sqrt{2} \)
4\( \sqrt{16 \times 2} \) + 9\( \sqrt{2} \)
4\( \sqrt{4^2 \times 2} \) + 9\( \sqrt{2} \)
(4)(4)\( \sqrt{2} \) + 9\( \sqrt{2} \)
16\( \sqrt{2} \) + 9\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

16\( \sqrt{2} \) + 9\( \sqrt{2} \)
(16 + 9)\( \sqrt{2} \)
25\( \sqrt{2} \)