| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
Which of the following is not an integer?
-1 |
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0 |
|
1 |
|
\({1 \over 2}\) |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
The __________ is the smallest positive integer that is a multiple of two or more integers.
least common factor |
|
absolute value |
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greatest common factor |
|
least common multiple |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
What is \( \frac{-5y^6}{2y^2} \)?
| -2\(\frac{1}{2}\)y12 | |
| -2\(\frac{1}{2}\)y4 | |
| -2\(\frac{1}{2}\)y3 | |
| -\(\frac{2}{5}\)y4 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-5y^6}{2y^2} \)
\( \frac{-5}{2} \) y(6 - 2)
-2\(\frac{1}{2}\)y4
If \( \left|y + 3\right| \) - 5 = 3, which of these is a possible value for y?
| -9 | |
| 5 | |
| 4 | |
| 14 |
First, solve for \( \left|y + 3\right| \):
\( \left|y + 3\right| \) - 5 = 3
\( \left|y + 3\right| \) = 3 + 5
\( \left|y + 3\right| \) = 8
The value inside the absolute value brackets can be either positive or negative so (y + 3) must equal + 8 or -8 for \( \left|y + 3\right| \) to equal 8:
| y + 3 = 8 y = 8 - 3 y = 5 | y + 3 = -8 y = -8 - 3 y = -11 |
So, y = -11 or y = 5.
What is \( 4 \)\( \sqrt{32} \) + \( 9 \)\( \sqrt{2} \)
| 25\( \sqrt{2} \) | |
| 13\( \sqrt{64} \) | |
| 13\( \sqrt{32} \) | |
| 13\( \sqrt{16} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{32} \) + 9\( \sqrt{2} \)
4\( \sqrt{16 \times 2} \) + 9\( \sqrt{2} \)
4\( \sqrt{4^2 \times 2} \) + 9\( \sqrt{2} \)
(4)(4)\( \sqrt{2} \) + 9\( \sqrt{2} \)
16\( \sqrt{2} \) + 9\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
16\( \sqrt{2} \) + 9\( \sqrt{2} \)