| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.82 |
| Score | 0% | 56% |
Which of the following is an improper fraction?
\({a \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({2 \over 5} \) |
|
\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
The __________ is the smallest positive integer that is a multiple of two or more integers.
least common factor |
|
absolute value |
|
least common multiple |
|
greatest common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
If all of a roofing company's 8 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 12 | |
| 19 | |
| 1 | |
| 6 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 4 crews so there are \( \frac{8}{4} \) = 2 workers on a crew. 7 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 7 x 2 = 14 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 14 - 8 = 6 new staff for the busy season.
What is \( \frac{-6a^5}{9a^2} \)?
| -1\(\frac{1}{2}\)a7 | |
| -\(\frac{2}{3}\)a3 | |
| -1\(\frac{1}{2}\)a3 | |
| -\(\frac{2}{3}\)a10 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-6a^5}{9a^2} \)
\( \frac{-6}{9} \) a(5 - 2)
-\(\frac{2}{3}\)a3
What is \( 8 \)\( \sqrt{75} \) - \( 5 \)\( \sqrt{3} \)
| 3\( \sqrt{75} \) | |
| 35\( \sqrt{3} \) | |
| 40\( \sqrt{75} \) | |
| 3\( \sqrt{225} \) |
To subtract these radicals together their radicands must be the same:
8\( \sqrt{75} \) - 5\( \sqrt{3} \)
8\( \sqrt{25 \times 3} \) - 5\( \sqrt{3} \)
8\( \sqrt{5^2 \times 3} \) - 5\( \sqrt{3} \)
(8)(5)\( \sqrt{3} \) - 5\( \sqrt{3} \)
40\( \sqrt{3} \) - 5\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
40\( \sqrt{3} \) - 5\( \sqrt{3} \)