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To subtract these radicals together their radicands must be the same:

9\( \sqrt{8} \) - 4\( \sqrt{2} \)
9\( \sqrt{4 \times 2} \) - 4\( \sqrt{2} \)
9\( \sqrt{2^2 \times 2} \) - 4\( \sqrt{2} \)
(9)(2)\( \sqrt{2} \) - 4\( \sqrt{2} \)
18\( \sqrt{2} \) - 4\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

The equation for this sequence is:

a_n = a_n-1 + 3(n - 1)

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 3(6 - 1)
a₆ = 31 + 3(5)
a₆ = 46

There are 4 3-passenger taxis available so that's 4 x 3 = 12 total seats. There are 16 people needing transportation leaving 16 - 12 = 4 who will have to find other transportation.

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 3}{2 x 3} \) - \( \frac{3 x 1}{6 x 1} \)

\( \frac{6}{6} \) - \( \frac{3}{6} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{6 - 3}{6} \) = \( \frac{3}{6} \) = \(\frac{1}{2}\)