| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
A triathlon course includes a 400m swim, a 20.1km bike ride, and a 13.5km run. What is the total length of the race course?
| 41.2km | |
| 34km | |
| 59.3km | |
| 54.4km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 400 meters to kilometers, divide the distance by 1000 to get 0.4km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.4km + 20.1km + 13.5km
total distance = 34km
What is (x3)4?
| x12 | |
| x | |
| 4x3 | |
| 3x4 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x3)4If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?
| 162 m2 | |
| 8 m2 | |
| 50 m2 | |
| 2 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.
Putting these two equations together and solving for width (w):
2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5
Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
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commutative property for multiplication |
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distributive property for division |
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commutative property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
What is \( \frac{4}{5} \) x \( \frac{3}{5} \)?
| \(\frac{12}{25}\) | |
| \(\frac{1}{16}\) | |
| \(\frac{1}{32}\) | |
| \(\frac{8}{35}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{5} \) x \( \frac{3}{5} \) = \( \frac{4 x 3}{5 x 5} \) = \( \frac{12}{25} \) = \(\frac{12}{25}\)