ASVAB Arithmetic Reasoning Practice Test 35727 Results

Your Results Global Average
Questions 5 5
Correct 0 3.30
Score 0% 66%

Review

1

53% Answer Correctly
1.8
7.2
1.2
1

Solution


1


2

What is \( \frac{1}{7} \) x \( \frac{2}{9} \)?

72% Answer Correctly
\(\frac{1}{28}\)
\(\frac{2}{9}\)
\(\frac{8}{25}\)
\(\frac{2}{63}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{7} \) x \( \frac{2}{9} \) = \( \frac{1 x 2}{7 x 9} \) = \( \frac{2}{63} \) = \(\frac{2}{63}\)


3

Which of the following is a mixed number?

82% Answer Correctly

\({a \over 5} \)

\({7 \over 5} \)

\({5 \over 7} \)

\(1 {2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

commutative property for division

distributive property for division

commutative property for multiplication

distributive property for multiplication


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.


5

On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 20 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
36
27
33
19

Solution
If the guard hits 50% of his shots and takes 20 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{50}{100} \) = \( \frac{50 x 20}{100} \) = \( \frac{1000}{100} \) = 10 shots

The center makes 30% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{10}{\frac{30}{100}} \) = 10 x \( \frac{100}{30} \) = \( \frac{10 x 100}{30} \) = \( \frac{1000}{30} \) = 33 shots

to make the same number of shots as the guard and thus score the same number of points.