ASVAB Arithmetic Reasoning Practice Test 357990 Results

Your Results Global Average
Questions 5 5
Correct 0 2.73
Score 0% 55%

Review

1

What is \( 8 \)\( \sqrt{175} \) + \( 2 \)\( \sqrt{7} \)

35% Answer Correctly
16\( \sqrt{7} \)
42\( \sqrt{7} \)
16\( \sqrt{1225} \)
16\( \sqrt{25} \)

Solution

To add these radicals together their radicands must be the same:

8\( \sqrt{175} \) + 2\( \sqrt{7} \)
8\( \sqrt{25 \times 7} \) + 2\( \sqrt{7} \)
8\( \sqrt{5^2 \times 7} \) + 2\( \sqrt{7} \)
(8)(5)\( \sqrt{7} \) + 2\( \sqrt{7} \)
40\( \sqrt{7} \) + 2\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

40\( \sqrt{7} \) + 2\( \sqrt{7} \)
(40 + 2)\( \sqrt{7} \)
42\( \sqrt{7} \)


2

Monty loaned Alex $700 at an annual interest rate of 2%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$84
$14
$60
$75

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $700
i = 0.02 x $700
i = $14


3

What is \( \frac{3}{2} \) + \( \frac{3}{4} \)?

59% Answer Correctly
2\(\frac{1}{4}\)
\( \frac{1}{10} \)
2 \( \frac{2}{9} \)
2 \( \frac{9}{15} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40]. The first few multiples they share are [4, 8, 12, 16, 20] making 4 the smallest multiple 2 and 4 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{3 x 2}{2 x 2} \) + \( \frac{3 x 1}{4 x 1} \)

\( \frac{6}{4} \) + \( \frac{3}{4} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{6 + 3}{4} \) = \( \frac{9}{4} \) = 2\(\frac{1}{4}\)


4

If the ratio of home fans to visiting fans in a crowd is 5:1 and all 32,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
36,000
24,667
23,250
26,667

Solution

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

32,000 fans x \( \frac{5}{6} \) = \( \frac{160000}{6} \) = 26,667 fans.


5

If all of a roofing company's 15 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?

55% Answer Correctly
17
15
5
9

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 15 workers at the company now and that's enough to staff 5 crews so there are \( \frac{15}{5} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 15 workers so they need to add 24 - 15 = 9 new staff for the busy season.