| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.30 |
| Score | 0% | 66% |
How many 7-passenger vans will it take to drive all 38 members of the football team to an away game?
| 7 vans | |
| 6 vans | |
| 8 vans | |
| 3 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{38}{7} \) = 5\(\frac{3}{7}\)
So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.
On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 35% of his shots. If the guard takes 30 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 27 | |
| 23 | |
| 33 | |
| 19 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{35}{100} \) = \( \frac{35 x 30}{100} \) = \( \frac{1050}{100} \) = 10 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{10}{\frac{30}{100}} \) = 10 x \( \frac{100}{30} \) = \( \frac{10 x 100}{30} \) = \( \frac{1000}{30} \) = 33 shots
to make the same number of shots as the guard and thus score the same number of points.
What is \( \frac{4}{7} \) x \( \frac{2}{7} \)?
| \(\frac{2}{25}\) | |
| \(\frac{8}{49}\) | |
| \(\frac{2}{27}\) | |
| \(\frac{3}{49}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{7} \) x \( \frac{2}{7} \) = \( \frac{4 x 2}{7 x 7} \) = \( \frac{8}{49} \) = \(\frac{8}{49}\)
What is 6y3 x 5y2?
| 11y5 | |
| 11y3 | |
| 30y5 | |
| 30y-1 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
6y3 x 5y2
(6 x 5)y(3 + 2)
30y5
Jennifer scored 97% on her final exam. If each question was worth 3 points and there were 180 possible points on the exam, how many questions did Jennifer answer correctly?
| 53 | |
| 58 | |
| 43 | |
| 63 |
Jennifer scored 97% on the test meaning she earned 97% of the possible points on the test. There were 180 possible points on the test so she earned 180 x 0.97 = 174 points. Each question is worth 3 points so she got \( \frac{174}{3} \) = 58 questions right.