ASVAB Arithmetic Reasoning Practice Test 35960 Results

Your Results Global Average
Questions 5 5
Correct 0 3.40
Score 0% 68%

Review

1

What is (y2)5?

80% Answer Correctly
5y2
y7
y3
y10

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(y2)5
y(2 * 5)
y10


2

What is the greatest common factor of 64 and 40?

77% Answer Correctly
22
8
29
18

Solution

The factors of 64 are [1, 2, 4, 8, 16, 32, 64] and the factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40]. They share 4 factors [1, 2, 4, 8] making 8 the greatest factor 64 and 40 have in common.


3

What is -6x3 - x3?

71% Answer Correctly
-5x6
-7x3
-7x-3
-5x9

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

-6x3 - 1x3
(-6 - 1)x3
-7x3


4

Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 11 small cakes per hour. The kitchen is available for 2 hours and 40 large cakes and 230 small cakes need to be baked.

How many cooks are required to bake the required number of cakes during the time the kitchen is available?

41% Answer Correctly
8
21
5
10

Solution

If a single cook can bake 2 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 2 x 2 = 4 large cakes during that time. 40 large cakes are needed for the party so \( \frac{40}{4} \) = 10 cooks are needed to bake the required number of large cakes.

If a single cook can bake 11 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 11 x 2 = 22 small cakes during that time. 230 small cakes are needed for the party so \( \frac{230}{22} \) = 10\(\frac{5}{11}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 10 + 11 = 21 cooks.


5

What is \( \frac{63\sqrt{27}}{9\sqrt{9}} \)?

71% Answer Correctly
7 \( \sqrt{3} \)
\(\frac{1}{7}\) \( \sqrt{\frac{1}{3}} \)
\(\frac{1}{3}\) \( \sqrt{\frac{1}{7}} \)
\(\frac{1}{3}\) \( \sqrt{7} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{63\sqrt{27}}{9\sqrt{9}} \)
\( \frac{63}{9} \) \( \sqrt{\frac{27}{9}} \)
7 \( \sqrt{3} \)