| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.25 |
| Score | 0% | 65% |
Which of the following is not an integer?
0 |
|
1 |
|
-1 |
|
\({1 \over 2}\) |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
What is -c2 x 9c3?
| -9c5 | |
| 8c6 | |
| -9c-1 | |
| -9c2 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-c2 x 9c3
(-1 x 9)c(2 + 3)
-9c5
Find the average of the following numbers: 14, 10, 16, 8.
| 16 | |
| 13 | |
| 12 | |
| 17 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{14 + 10 + 16 + 8}{4} \) = \( \frac{48}{4} \) = 12
What is 9\( \sqrt{4} \) x 7\( \sqrt{4} \)?
| 16\( \sqrt{16} \) | |
| 252 | |
| 63\( \sqrt{4} \) | |
| 16\( \sqrt{4} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
9\( \sqrt{4} \) x 7\( \sqrt{4} \)
(9 x 7)\( \sqrt{4 \times 4} \)
63\( \sqrt{16} \)
Now we need to simplify the radical:
63\( \sqrt{16} \)
63\( \sqrt{4^2} \)
(63)(4)
252
A tiger in a zoo has consumed 65 pounds of food in 5 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 143 pounds?
| 4 | |
| 3 | |
| 8 | |
| 6 |
If the tiger has consumed 65 pounds of food in 5 days that's \( \frac{65}{5} \) = 13 pounds of food per day. The tiger needs to consume 143 - 65 = 78 more pounds of food to reach 143 pounds total. At 13 pounds of food per day that's \( \frac{78}{13} \) = 6 more days.