ASVAB Arithmetic Reasoning Practice Test 362458 Results

Your Results Global Average
Questions 5 5
Correct 0 3.06
Score 0% 61%

Review

1

Simplify \( \sqrt{75} \)

62% Answer Correctly
9\( \sqrt{6} \)
4\( \sqrt{3} \)
7\( \sqrt{3} \)
5\( \sqrt{3} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{75} \)
\( \sqrt{25 \times 3} \)
\( \sqrt{5^2 \times 3} \)
5\( \sqrt{3} \)


2

What is \( \frac{3}{8} \) ÷ \( \frac{4}{9} \)?

68% Answer Correctly
\(\frac{1}{36}\)
\(\frac{4}{15}\)
\(\frac{27}{32}\)
\(\frac{4}{63}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{3}{8} \) ÷ \( \frac{4}{9} \) = \( \frac{3}{8} \) x \( \frac{9}{4} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{8} \) x \( \frac{9}{4} \) = \( \frac{3 x 9}{8 x 4} \) = \( \frac{27}{32} \) = \(\frac{27}{32}\)


3

In a class of 20 students, 5 are taking German and 12 are taking Spanish. Of the students studying German or Spanish, 5 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
11
10
8
16

Solution

The number of students taking German or Spanish is 5 + 12 = 17. Of that group of 17, 5 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 17 - 5 = 12 who are taking at least one language. 20 - 12 = 8 students who are not taking either language.


4

If the ratio of home fans to visiting fans in a crowd is 5:1 and all 39,000 seats in a stadium are filled, how many home fans are in attendance?

49% Answer Correctly
27,333
30,000
32,500
30,750

Solution

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

39,000 fans x \( \frac{5}{6} \) = \( \frac{195000}{6} \) = 32,500 fans.


5

What is \( \frac{7}{3} \) - \( \frac{3}{5} \)?

61% Answer Correctly
2 \( \frac{9}{15} \)
1\(\frac{11}{15}\)
1 \( \frac{4}{15} \)
2 \( \frac{7}{12} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{7 x 5}{3 x 5} \) - \( \frac{3 x 3}{5 x 3} \)

\( \frac{35}{15} \) - \( \frac{9}{15} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{35 - 9}{15} \) = \( \frac{26}{15} \) = 1\(\frac{11}{15}\)