ASVAB Arithmetic Reasoning Practice Test 362886 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

If there were a total of 450 raffle tickets sold and you bought 9 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
14%
9%
15%
2%

Solution

You have 9 out of the total of 450 raffle tickets sold so you have a (\( \frac{9}{450} \)) x 100 = \( \frac{9 \times 100}{450} \) = \( \frac{900}{450} \) = 2% chance to win the raffle.


2

What is 8a7 x 4a4?

75% Answer Correctly
12a11
32a4
32a7
32a11

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

8a7 x 4a4
(8 x 4)a(7 + 4)
32a11


3

What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?

68% Answer Correctly
55
64
59
61

Solution

The equation for this sequence is:

an = an-1 + 4(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61


4

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

distributive property for multiplication

distributive property for division

commutative property for multiplication

commutative property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


5

A tiger in a zoo has consumed 100 pounds of food in 10 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 130 pounds?

56% Answer Correctly
3
10
6
9

Solution

If the tiger has consumed 100 pounds of food in 10 days that's \( \frac{100}{10} \) = 10 pounds of food per day. The tiger needs to consume 130 - 100 = 30 more pounds of food to reach 130 pounds total. At 10 pounds of food per day that's \( \frac{30}{10} \) = 3 more days.