ASVAB Arithmetic Reasoning Practice Test 363539 Results

Your Results Global Average
Questions 5 5
Correct 0 2.95
Score 0% 59%

Review

1

Simplify \( \frac{28}{72} \).

77% Answer Correctly
\( \frac{5}{14} \)
\( \frac{7}{20} \)
\( \frac{7}{18} \)
\( \frac{9}{20} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{28}{72} \) = \( \frac{\frac{28}{4}}{\frac{72}{4}} \) = \( \frac{7}{18} \)


2

What is \( 6 \)\( \sqrt{80} \) + \( 7 \)\( \sqrt{5} \)

35% Answer Correctly
31\( \sqrt{5} \)
13\( \sqrt{16} \)
42\( \sqrt{5} \)
13\( \sqrt{80} \)

Solution

To add these radicals together their radicands must be the same:

6\( \sqrt{80} \) + 7\( \sqrt{5} \)
6\( \sqrt{16 \times 5} \) + 7\( \sqrt{5} \)
6\( \sqrt{4^2 \times 5} \) + 7\( \sqrt{5} \)
(6)(4)\( \sqrt{5} \) + 7\( \sqrt{5} \)
24\( \sqrt{5} \) + 7\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

24\( \sqrt{5} \) + 7\( \sqrt{5} \)
(24 + 7)\( \sqrt{5} \)
31\( \sqrt{5} \)


3

If all of a roofing company's 6 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 4 complete crews out on jobs?

55% Answer Correctly
5
15
17
6

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 2 crews so there are \( \frac{6}{2} \) = 3 workers on a crew. 4 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 4 x 3 = 12 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 12 - 6 = 6 new staff for the busy season.


4

If a rectangle is twice as long as it is wide and has a perimeter of 6 meters, what is the area of the rectangle?

47% Answer Correctly
2 m2
8 m2
18 m2
72 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 6 meters so the equation becomes: 2w + 2h = 6.

Putting these two equations together and solving for width (w):

2w + 2h = 6
w + h = \( \frac{6}{2} \)
w + h = 3
w = 3 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 3 - 2w
3w = 3
w = \( \frac{3}{3} \)
w = 1

Since h = 2w that makes h = (2 x 1) = 2 and the area = h x w = 1 x 2 = 2 m2


5

What is the greatest common factor of 28 and 60?

77% Answer Correctly
23
4
8
16

Solution

The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 3 factors [1, 2, 4] making 4 the greatest factor 28 and 60 have in common.