ASVAB Arithmetic Reasoning Practice Test 364277 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.36
Score	0%	67%

Review

Simplify $ \sqrt{75} $

62% Answer Correctly

	8$ \sqrt{6} $
	5$ \sqrt{3} $
	4$ \sqrt{6} $
	2$ \sqrt{6} $

Solution

To simplify a radical, factor out the perfect squares:

$ \sqrt{75} $
$ \sqrt{25 \times 3} $
$ \sqrt{5^2 \times 3} $
5$ \sqrt{3} $

How many 16-passenger vans will it take to drive all 52 members of the football team to an away game?

81% Answer Correctly

	4 vans
	3 vans
	7 vans
	6 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = $ \frac{52}{16} $ = 3$\frac{1}{4}$

So, it will take 3 full vans and one partially full van to transport the entire team making a total of 4 vans.

A bread recipe calls for 3$\frac{3}{8}$ cups of flour. If you only have $\frac{5}{8}$ cup, how much more flour is needed?

62% Answer Correctly

	2$\frac{3}{4}$ cups
	2$\frac{1}{4}$ cups
	2$\frac{1}{8}$ cups
	2$\frac{5}{8}$ cups

Solution

The amount of flour you need is (3$\frac{3}{8}$ - $\frac{5}{8}$) cups. Rewrite the quantities so they share a common denominator and subtract:

($ \frac{27}{8} $ - $ \frac{5}{8} $) cups
$ \frac{22}{8} $ cups
2$\frac{3}{4}$ cups

What is $ \frac{7a^5}{6a^3} $?

60% Answer Correctly

	1$\frac{1}{6}$a¹⁵
	$\frac{6}{7}$a⁸
	$\frac{6}{7}$a^-2
	1$\frac{1}{6}$a²

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

$ \frac{7a^5}{6a^3} $
$ \frac{7}{6} $ a^{(5 - 3)}
1$\frac{1}{6}$a²

Frank loaned Betty $300 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly

	$309
	$318
	$312
	$327

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $300
i = 0.06 x $300

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $300 + $18
total = $318

	8\( \sqrt{6} \)
	5\( \sqrt{3} \)
	4\( \sqrt{6} \)
	2\( \sqrt{6} \)

	2\(\frac{3}{4}\) cups
	2\(\frac{1}{4}\) cups
	2\(\frac{1}{8}\) cups
	2\(\frac{5}{8}\) cups

	1\(\frac{1}{6}\)a¹⁵
	\(\frac{6}{7}\)a⁸
	\(\frac{6}{7}\)a^-2
	1\(\frac{1}{6}\)a²