ASVAB Arithmetic Reasoning Practice Test 366437 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.07
Score	0%	61%

Review

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

	greatest common factor
	least common multiple
	greatest common multiple
	absolute value

Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 35% off." If Monty buys two shirts, each with a regular price of $23, how much money will he save?

70% Answer Correctly

	$8.05
	$5.75
	$4.60
	$9.20

Solution

By buying two shirts, Monty will save $23 x $ \frac{35}{100} $ = $ \frac{$23 x 35}{100} $ = $ \frac{$805}{100} $ = $8.05 on the second shirt.

If $ \left|c - 1\right| $ + 0 = -1, which of these is a possible value for c?

62% Answer Correctly

	5
	9
	2
	-2

Solution

First, solve for $ \left|c - 1\right| $:

The value inside the absolute value brackets can be either positive or negative so (c - 1) must equal - 1 or --1 for $ \left|c - 1\right| $ to equal -1:

c - 1 = -1
c = -1 + 1
c = 0

c - 1 = 1
c = 1 + 1
c = 2

So, c = 2 or c = 0.

What is $ 8 $$ \sqrt{125} $ - $ 4 $$ \sqrt{5} $

38% Answer Correctly

	32$ \sqrt{5} $
	32$ \sqrt{125} $
	36$ \sqrt{5} $
	32$ \sqrt{25} $

Solution

To subtract these radicals together their radicands must be the same:

8$ \sqrt{125} $ - 4$ \sqrt{5} $
8$ \sqrt{25 \times 5} $ - 4$ \sqrt{5} $
8$ \sqrt{5^2 \times 5} $ - 4$ \sqrt{5} $
(8)(5)$ \sqrt{5} $ - 4$ \sqrt{5} $
40$ \sqrt{5} $ - 4$ \sqrt{5} $

Now that the radicands are identical, you can subtract them:

40$ \sqrt{5} $ - 4$ \sqrt{5} $
(40 - 4)$ \sqrt{5} $
36$ \sqrt{5} $

What is $ \frac{4}{6} $ ÷ $ \frac{2}{7} $?

68% Answer Correctly

	2$\frac{1}{3}$
	$\frac{1}{21}$
	4$\frac{2}{3}$
	$\frac{2}{27}$

Solution

To divide fractions, invert the second fraction and then multiply:

$ \frac{4}{6} $ ÷ $ \frac{2}{7} $ = $ \frac{4}{6} $ x $ \frac{7}{2} $

To multiply fractions, multiply the numerators together and then multiply the denominators together:

$ \frac{4}{6} $ x $ \frac{7}{2} $ = $ \frac{4 x 7}{6 x 2} $ = $ \frac{28}{12} $ = 2$\frac{1}{3}$

	32\( \sqrt{5} \)
	32\( \sqrt{125} \)
	36\( \sqrt{5} \)
	32\( \sqrt{25} \)

	2\(\frac{1}{3}\)
	\(\frac{1}{21}\)
	4\(\frac{2}{3}\)
	\(\frac{2}{27}\)