ASVAB Arithmetic Reasoning Practice Test 366629 Results

Your Results Global Average
Questions 5 5
Correct 0 3.37
Score 0% 67%

Review

1

What is 9z3 - 7z3?

71% Answer Correctly
16z-6
2z-3
2z3
16z6

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

9z3 - 7z3
(9 - 7)z3
2z3


2

What is the least common multiple of 2 and 6?

72% Answer Correctly
6
3
4
1

Solution

The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 have in common.


3

Which of the following is not an integer?

77% Answer Correctly

\({1 \over 2}\)

0

-1

1


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


4

What is \( 4 \)\( \sqrt{8} \) + \( 4 \)\( \sqrt{2} \)

35% Answer Correctly
16\( \sqrt{16} \)
8\( \sqrt{8} \)
12\( \sqrt{2} \)
8\( \sqrt{16} \)

Solution

To add these radicals together their radicands must be the same:

4\( \sqrt{8} \) + 4\( \sqrt{2} \)
4\( \sqrt{4 \times 2} \) + 4\( \sqrt{2} \)
4\( \sqrt{2^2 \times 2} \) + 4\( \sqrt{2} \)
(4)(2)\( \sqrt{2} \) + 4\( \sqrt{2} \)
8\( \sqrt{2} \) + 4\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

8\( \sqrt{2} \) + 4\( \sqrt{2} \)
(8 + 4)\( \sqrt{2} \)
12\( \sqrt{2} \)


5

What is (b3)4?

79% Answer Correctly
b-1
4b3
b7
b12

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(b3)4
b(3 * 4)
b12