| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
7 members of a bridal party need transported to a wedding reception but there are only 3 2-passenger taxis available to take them. How many will need to find other transportation?
| 3 | |
| 1 | |
| 8 | |
| 5 |
There are 3 2-passenger taxis available so that's 3 x 2 = 6 total seats. There are 7 people needing transportation leaving 7 - 6 = 1 who will have to find other transportation.
Simplify \( \sqrt{112} \)
| 8\( \sqrt{7} \) | |
| 4\( \sqrt{7} \) | |
| 6\( \sqrt{14} \) | |
| 5\( \sqrt{14} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{112} \)
\( \sqrt{16 \times 7} \)
\( \sqrt{4^2 \times 7} \)
4\( \sqrt{7} \)
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
PEDMAS |
|
distributive |
|
associative |
|
commutative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
If a rectangle is twice as long as it is wide and has a perimeter of 48 meters, what is the area of the rectangle?
| 162 m2 | |
| 128 m2 | |
| 32 m2 | |
| 2 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 48 meters so the equation becomes: 2w + 2h = 48.
Putting these two equations together and solving for width (w):
2w + 2h = 48
w + h = \( \frac{48}{2} \)
w + h = 24
w = 24 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 24 - 2w
3w = 24
w = \( \frac{24}{3} \)
w = 8
Since h = 2w that makes h = (2 x 8) = 16 and the area = h x w = 8 x 16 = 128 m2
What is \( \frac{-9x^7}{9x^2} \)?
| -x-5 | |
| -x9 | |
| -x3\(\frac{1}{2}\) | |
| -x5 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-9x^7}{9x^2} \)
\( \frac{-9}{9} \) x(7 - 2)
-x5