ASVAB Arithmetic Reasoning Practice Test 36758 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

What is (a4)4?

79% Answer Correctly
a8
4a4
a0
a16

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(a4)4
a(4 * 4)
a16


2

If all of a roofing company's 12 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 5 complete crews out on jobs?

55% Answer Correctly
4
14
8
5

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 3 crews so there are \( \frac{12}{3} \) = 4 workers on a crew. 5 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 5 x 4 = 20 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 20 - 12 = 8 new staff for the busy season.


3

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 5% off." If Frank buys two shirts, each with a regular price of $25, how much will he pay for both shirts?

57% Answer Correctly
$35.00
$48.75
$1.25
$28.75

Solution

By buying two shirts, Frank will save $25 x \( \frac{5}{100} \) = \( \frac{$25 x 5}{100} \) = \( \frac{$125}{100} \) = $1.25 on the second shirt.

So, his total cost will be
$25.00 + ($25.00 - $1.25)
$25.00 + $23.75
$48.75


4

What is \( \frac{4}{5} \) ÷ \( \frac{3}{7} \)?

68% Answer Correctly
\(\frac{1}{27}\)
\(\frac{3}{10}\)
9\(\frac{1}{3}\)
1\(\frac{13}{15}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{5} \) ÷ \( \frac{3}{7} \) = \( \frac{4}{5} \) x \( \frac{7}{3} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{5} \) x \( \frac{7}{3} \) = \( \frac{4 x 7}{5 x 3} \) = \( \frac{28}{15} \) = 1\(\frac{13}{15}\)


5

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

least common factor

greatest common factor

least common multiple


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.