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Questions | 5 | 5 |
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This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
commutative |
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PEDMAS |
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distributive |
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associative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
If a rectangle is twice as long as it is wide and has a perimeter of 6 meters, what is the area of the rectangle?
2 m2 | |
72 m2 | |
50 m2 | |
8 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 6 meters so the equation becomes: 2w + 2h = 6.
Putting these two equations together and solving for width (w):
2w + 2h = 6
w + h = \( \frac{6}{2} \)
w + h = 3
w = 3 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 3 - 2w
3w = 3
w = \( \frac{3}{3} \)
w = 1
Since h = 2w that makes h = (2 x 1) = 2 and the area = h x w = 1 x 2 = 2 m2
Which of the following statements about exponents is false?
b1 = b |
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b0 = 1 |
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b1 = 1 |
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all of these are false |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
A bread recipe calls for 2\(\frac{3}{8}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?
2\(\frac{1}{4}\) cups | |
3\(\frac{3}{8}\) cups | |
\(\frac{1}{2}\) cups | |
1\(\frac{7}{8}\) cups |
The amount of flour you need is (2\(\frac{3}{8}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{19}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{15}{8} \) cups
1\(\frac{7}{8}\) cups
What is \( \frac{9a^6}{1a^3} \)?
9a3 | |
\(\frac{1}{9}\)a-3 | |
9a18 | |
9a2 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{9a^6}{a^3} \)
\( \frac{9}{1} \) a(6 - 3)
9a3