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|---|---|---|
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The __________ is the greatest factor that divides two integers.
least common multiple |
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absolute value |
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greatest common factor |
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greatest common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
What is (x5)3?
| x8 | |
| x2 | |
| x15 | |
| 5x3 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x5)3What is \( \frac{8}{8} \) - \( \frac{5}{10} \)?
| \( \frac{6}{10} \) | |
| \(\frac{1}{2}\) | |
| 2 \( \frac{4}{10} \) | |
| 2 \( \frac{3}{40} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [40, 80] making 40 the smallest multiple 8 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{8 x 5}{8 x 5} \) - \( \frac{5 x 4}{10 x 4} \)
\( \frac{40}{40} \) - \( \frac{20}{40} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{40 - 20}{40} \) = \( \frac{20}{40} \) = \(\frac{1}{2}\)
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
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commutative property for division |
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distributive property for multiplication |
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distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 55% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 15 | |
| 23 | |
| 32 | |
| 38 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{55}{100} \) = \( \frac{55 x 15}{100} \) = \( \frac{825}{100} \) = 8 shots
The center makes 35% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{8}{\frac{35}{100}} \) = 8 x \( \frac{100}{35} \) = \( \frac{8 x 100}{35} \) = \( \frac{800}{35} \) = 23 shots
to make the same number of shots as the guard and thus score the same number of points.