The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 5}{3 x 5} \) - \( \frac{4 x 3}{5 x 3} \)

\( \frac{10}{15} \) - \( \frac{12}{15} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{10 - 12}{15} \) = \( \frac{-2}{15} \) = -\(\frac{2}{15}\)

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-4b⁴ x 7b²
(-4 x 7)b^{(4 + 2)}
-28b⁶

By buying two shirts, Monty will save $29 x \( \frac{30}{100} \) = \( \frac{$29 x 30}{100} \) = \( \frac{$870}{100} \) = $8.70 on the second shirt.

So, his total cost will be
$29.00 + ($29.00 - $8.70)
$29.00 + $20.30
$49.30

To subtract these radicals together their radicands must be the same:

6\( \sqrt{32} \) - 6\( \sqrt{2} \)
6\( \sqrt{16 \times 2} \) - 6\( \sqrt{2} \)
6\( \sqrt{4^2 \times 2} \) - 6\( \sqrt{2} \)
(6)(4)\( \sqrt{2} \) - 6\( \sqrt{2} \)
24\( \sqrt{2} \) - 6\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them: