ASVAB Arithmetic Reasoning Practice Test 372413 Results

Your Results Global Average
Questions 5 5
Correct 0 3.49
Score 0% 70%

Review

1

Frank loaned Bob $500 at an annual interest rate of 6%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$2
$112
$42
$30

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $500
i = 0.06 x $500
i = $30


2

4! = ?

85% Answer Correctly

4 x 3 x 2 x 1

4 x 3

3 x 2 x 1

5 x 4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


3

What is the next number in this sequence: 1, 10, 19, 28, 37, __________ ?

92% Answer Correctly
48
49
46
52

Solution

The equation for this sequence is:

an = an-1 + 9

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 9
a6 = 37 + 9
a6 = 46


4

A bread recipe calls for 2\(\frac{1}{8}\) cups of flour. If you only have 1\(\frac{1}{4}\) cups, how much more flour is needed?

62% Answer Correctly
1\(\frac{1}{4}\) cups
2\(\frac{1}{8}\) cups
\(\frac{7}{8}\) cups
2\(\frac{5}{8}\) cups

Solution

The amount of flour you need is (2\(\frac{1}{8}\) - 1\(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{17}{8} \) - \( \frac{10}{8} \)) cups
\( \frac{7}{8} \) cups
\(\frac{7}{8}\) cups


5

What is \( 4 \)\( \sqrt{48} \) + \( 4 \)\( \sqrt{3} \)

35% Answer Correctly
8\( \sqrt{144} \)
20\( \sqrt{3} \)
16\( \sqrt{16} \)
8\( \sqrt{16} \)

Solution

To add these radicals together their radicands must be the same:

4\( \sqrt{48} \) + 4\( \sqrt{3} \)
4\( \sqrt{16 \times 3} \) + 4\( \sqrt{3} \)
4\( \sqrt{4^2 \times 3} \) + 4\( \sqrt{3} \)
(4)(4)\( \sqrt{3} \) + 4\( \sqrt{3} \)
16\( \sqrt{3} \) + 4\( \sqrt{3} \)

Now that the radicands are identical, you can add them together:

16\( \sqrt{3} \) + 4\( \sqrt{3} \)
(16 + 4)\( \sqrt{3} \)
20\( \sqrt{3} \)