| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
In a class of 38 students, 15 are taking German and 14 are taking Spanish. Of the students studying German or Spanish, 5 are taking both courses. How many students are not enrolled in either course?
| 25 | |
| 32 | |
| 14 | |
| 34 |
The number of students taking German or Spanish is 15 + 14 = 29. Of that group of 29, 5 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 29 - 5 = 24 who are taking at least one language. 38 - 24 = 14 students who are not taking either language.
If all of a roofing company's 4 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 14 | |
| 10 | |
| 19 | |
| 2 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 4 workers at the company now and that's enough to staff 2 crews so there are \( \frac{4}{2} \) = 2 workers on a crew. 7 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 7 x 2 = 14 total workers to staff the crews during the busy season. The company already employs 4 workers so they need to add 14 - 4 = 10 new staff for the busy season.
The total water usage for a city is 45,000 gallons each day. Of that total, 30% is for personal use and 60% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 13,500 | |
| 5,200 | |
| 11,900 | |
| 7,200 |
60% of the water consumption is industrial use and 30% is personal use so (60% - 30%) = 30% more water is used for industrial purposes. 45,000 gallons are consumed daily so industry consumes \( \frac{30}{100} \) x 45,000 gallons = 13,500 gallons.
The __________ is the greatest factor that divides two integers.
least common multiple |
|
absolute value |
|
greatest common factor |
|
greatest common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 12 gallon tank to fill it exactly halfway?
| 9 | |
| 4 | |
| 3 | |
| 8 |
To fill a 12 gallon tank exactly halfway you'll need 6 gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{6 \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 4