| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.79 |
| Score | 0% | 56% |
If \( \left|x - 6\right| \) + 5 = 7, which of these is a possible value for x?
| -5 | |
| 1 | |
| 4 | |
| -6 |
First, solve for \( \left|x - 6\right| \):
\( \left|x - 6\right| \) + 5 = 7
\( \left|x - 6\right| \) = 7 - 5
\( \left|x - 6\right| \) = 2
The value inside the absolute value brackets can be either positive or negative so (x - 6) must equal + 2 or -2 for \( \left|x - 6\right| \) to equal 2:
| x - 6 = 2 x = 2 + 6 x = 8 | x - 6 = -2 x = -2 + 6 x = 4 |
So, x = 4 or x = 8.
Solve 2 + (5 + 5) ÷ 2 x 5 - 32
| \(\frac{5}{6}\) | |
| 18 | |
| 2 | |
| 1\(\frac{1}{2}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (5 + 5) ÷ 2 x 5 - 32
P: 2 + (10) ÷ 2 x 5 - 32
E: 2 + 10 ÷ 2 x 5 - 9
MD: 2 + \( \frac{10}{2} \) x 5 - 9
MD: 2 + \( \frac{50}{2} \) - 9
AS: \( \frac{4}{2} \) + \( \frac{50}{2} \) - 9
AS: \( \frac{54}{2} \) - 9
AS: \( \frac{54 - 18}{2} \)
\( \frac{36}{2} \)
18
Christine scored 98% on her final exam. If each question was worth 4 points and there were 400 possible points on the exam, how many questions did Christine answer correctly?
| 98 | |
| 91 | |
| 92 | |
| 89 |
Christine scored 98% on the test meaning she earned 98% of the possible points on the test. There were 400 possible points on the test so she earned 400 x 0.98 = 392 points. Each question is worth 4 points so she got \( \frac{392}{4} \) = 98 questions right.
| 1 | |
| 7.2 | |
| 2.4 | |
| 2.0 |
1
If all of a roofing company's 9 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 8 | |
| 14 | |
| 16 | |
| 15 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 9 workers at the company now and that's enough to staff 3 crews so there are \( \frac{9}{3} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 9 workers so they need to add 24 - 9 = 15 new staff for the busy season.