ASVAB Arithmetic Reasoning Practice Test 378017 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

A tiger in a zoo has consumed 24 pounds of food in 3 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 72 pounds?

56% Answer Correctly
8
1
2
6

Solution

If the tiger has consumed 24 pounds of food in 3 days that's \( \frac{24}{3} \) = 8 pounds of food per day. The tiger needs to consume 72 - 24 = 48 more pounds of food to reach 72 pounds total. At 8 pounds of food per day that's \( \frac{48}{8} \) = 6 more days.


2

53% Answer Correctly
0.2
1
1.2
2.4

Solution


1


3

7 members of a bridal party need transported to a wedding reception but there are only 2 3-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
8
2
7
1

Solution

There are 2 3-passenger taxis available so that's 2 x 3 = 6 total seats. There are 7 people needing transportation leaving 7 - 6 = 1 who will have to find other transportation.


4

A bread recipe calls for 2\(\frac{1}{8}\) cups of flour. If you only have 1\(\frac{3}{4}\) cups, how much more flour is needed?

62% Answer Correctly
2\(\frac{1}{2}\) cups
1\(\frac{3}{8}\) cups
\(\frac{3}{8}\) cups
3\(\frac{1}{8}\) cups

Solution

The amount of flour you need is (2\(\frac{1}{8}\) - 1\(\frac{3}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{17}{8} \) - \( \frac{14}{8} \)) cups
\( \frac{3}{8} \) cups
\(\frac{3}{8}\) cups


5

A machine in a factory has an error rate of 5 parts per 100. The machine normally runs 24 hours a day and produces 10 parts per hour. Yesterday the machine was shut down for 6 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
171
195.3
74.4
91.2

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{5}{100} \) x 10 = \( \frac{5 \times 10}{100} \) = \( \frac{50}{100} \) = 0.5 errors per hour

So, in an average hour, the machine will produce 10 - 0.5 = 9.5 error free parts.

The machine ran for 24 - 6 = 18 hours yesterday so you would expect that 18 x 9.5 = 171 error free parts were produced yesterday.