| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
commutative |
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PEDMAS |
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distributive |
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associative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
Find the average of the following numbers: 14, 8, 12, 10.
| 7 | |
| 15 | |
| 11 | |
| 14 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{14 + 8 + 12 + 10}{4} \) = \( \frac{44}{4} \) = 11
What is \( \frac{2}{3} \) + \( \frac{8}{5} \)?
| 2\(\frac{4}{15}\) | |
| 2 \( \frac{4}{15} \) | |
| 1 \( \frac{8}{15} \) | |
| 2 \( \frac{6}{15} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 5}{3 x 5} \) + \( \frac{8 x 3}{5 x 3} \)
\( \frac{10}{15} \) + \( \frac{24}{15} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{10 + 24}{15} \) = \( \frac{34}{15} \) = 2\(\frac{4}{15}\)
A tiger in a zoo has consumed 72 pounds of food in 8 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 108 pounds?
| 5 | |
| 8 | |
| 1 | |
| 4 |
If the tiger has consumed 72 pounds of food in 8 days that's \( \frac{72}{8} \) = 9 pounds of food per day. The tiger needs to consume 108 - 72 = 36 more pounds of food to reach 108 pounds total. At 9 pounds of food per day that's \( \frac{36}{9} \) = 4 more days.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 55% larger than the original. By what percentage has the area of the logo increased?
| 37\(\frac{1}{2}\)% | |
| 32\(\frac{1}{2}\)% | |
| 27\(\frac{1}{2}\)% | |
| 17\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 55% the radius (and, consequently, the total area) increases by \( \frac{55\text{%}}{2} \) = 27\(\frac{1}{2}\)%