| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
What is \( \frac{2}{7} \) ÷ \( \frac{3}{9} \)?
| \(\frac{4}{81}\) | |
| \(\frac{6}{7}\) | |
| \(\frac{4}{21}\) | |
| \(\frac{1}{3}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{7} \) ÷ \( \frac{3}{9} \) = \( \frac{2}{7} \) x \( \frac{9}{3} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{7} \) x \( \frac{9}{3} \) = \( \frac{2 x 9}{7 x 3} \) = \( \frac{18}{21} \) = \(\frac{6}{7}\)
Which of the following is not a prime number?
9 |
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2 |
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7 |
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5 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
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distributive property for division |
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commutative property for division |
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commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
a(b + c) = ab + ac defines which of the following?
commutative property for multiplication |
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commutative property for division |
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distributive property for multiplication |
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distributive property for division |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
What is \( \frac{7}{2} \) + \( \frac{3}{6} \)?
| 4 | |
| 1 \( \frac{3}{6} \) | |
| 2 \( \frac{1}{6} \) | |
| 2 \( \frac{8}{16} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 3}{2 x 3} \) + \( \frac{3 x 1}{6 x 1} \)
\( \frac{21}{6} \) + \( \frac{3}{6} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{21 + 3}{6} \) = \( \frac{24}{6} \) = 4