ASVAB Arithmetic Reasoning Practice Test 381107 Results

Your Results Global Average
Questions 5 5
Correct 0 3.39
Score 0% 68%

Review

1

What is \( \frac{4}{3} \) + \( \frac{9}{7} \)?

59% Answer Correctly
1 \( \frac{8}{21} \)
\( \frac{5}{21} \)
2\(\frac{13}{21}\)
2 \( \frac{5}{10} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{4 x 7}{3 x 7} \) + \( \frac{9 x 3}{7 x 3} \)

\( \frac{28}{21} \) + \( \frac{27}{21} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{28 + 27}{21} \) = \( \frac{55}{21} \) = 2\(\frac{13}{21}\)


2

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

integer

improper fraction

fraction

mixed number


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


3

What is \( \frac{-4c^5}{5c^3} \)?

60% Answer Correctly
-\(\frac{4}{5}\)c2
-\(\frac{4}{5}\)c15
-\(\frac{4}{5}\)c-2
-\(\frac{4}{5}\)c\(\frac{3}{5}\)

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-4c^5}{5c^3} \)
\( \frac{-4}{5} \) c(5 - 3)
-\(\frac{4}{5}\)c2


4

What is 5c2 + 3c2?

66% Answer Correctly
-2c2
-2c-2
8c2
8c4

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

5c2 + 3c2
(5 + 3)c2
8c2


5

What is 8b2 x 2b5?

75% Answer Correctly
10b5
10b7
16b3
16b7

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

8b2 x 2b5
(8 x 2)b(2 + 5)
16b7