| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.69 |
| Score | 0% | 74% |
Find the average of the following numbers: 12, 8, 14, 6.
| 8 | |
| 14 | |
| 10 | |
| 6 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{12 + 8 + 14 + 6}{4} \) = \( \frac{40}{4} \) = 10
If \(\left|a\right| = 7\), which of the following best describes a?
none of these is correct |
|
a = 7 |
|
a = -7 |
|
a = 7 or a = -7 |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
What is \( \frac{7}{9} \) + \( \frac{8}{15} \)?
| 1 \( \frac{6}{14} \) | |
| 1\(\frac{14}{45}\) | |
| \( \frac{1}{9} \) | |
| 2 \( \frac{7}{11} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 5}{9 x 5} \) + \( \frac{8 x 3}{15 x 3} \)
\( \frac{35}{45} \) + \( \frac{24}{45} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{35 + 24}{45} \) = \( \frac{59}{45} \) = 1\(\frac{14}{45}\)
4! = ?
4 x 3 x 2 x 1 |
|
4 x 3 |
|
3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
What is the distance in miles of a trip that takes 5 hours at an average speed of 65 miles per hour?
| 150 miles | |
| 325 miles | |
| 245 miles | |
| 225 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 65mph \times 5h \)
325 miles