ASVAB Arithmetic Reasoning Practice Test 382098 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

What is \( \frac{2}{6} \) x \( \frac{2}{6} \)?

72% Answer Correctly
\(\frac{1}{36}\)
\(\frac{4}{63}\)
\(\frac{1}{9}\)
\(\frac{3}{28}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{6} \) x \( \frac{2}{6} \) = \( \frac{2 x 2}{6 x 6} \) = \( \frac{4}{36} \) = \(\frac{1}{9}\)


2

What is 5b5 x 3b6?

75% Answer Correctly
8b6
15b6
15b11
15b-1

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

5b5 x 3b6
(5 x 3)b(5 + 6)
15b11


3

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

integer

fraction

mixed number

improper fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


4

What is \( 2 \)\( \sqrt{32} \) - \( 9 \)\( \sqrt{2} \)

38% Answer Correctly
-7\( \sqrt{32} \)
-7\( \sqrt{64} \)
-1\( \sqrt{2} \)
-7\( \sqrt{2} \)

Solution

To subtract these radicals together their radicands must be the same:

2\( \sqrt{32} \) - 9\( \sqrt{2} \)
2\( \sqrt{16 \times 2} \) - 9\( \sqrt{2} \)
2\( \sqrt{4^2 \times 2} \) - 9\( \sqrt{2} \)
(2)(4)\( \sqrt{2} \) - 9\( \sqrt{2} \)
8\( \sqrt{2} \) - 9\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

8\( \sqrt{2} \) - 9\( \sqrt{2} \)
(8 - 9)\( \sqrt{2} \)
-1\( \sqrt{2} \)


5

Convert a-3 to remove the negative exponent.

67% Answer Correctly
\( \frac{-1}{a^{-3}} \)
\( \frac{-3}{-a} \)
\( \frac{1}{a^3} \)
\( \frac{-3}{a} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.