| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.33 |
| Score | 0% | 67% |
What is \( \frac{2}{6} \) x \( \frac{2}{6} \)?
| \(\frac{1}{36}\) | |
| \(\frac{4}{63}\) | |
| \(\frac{1}{9}\) | |
| \(\frac{3}{28}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{6} \) x \( \frac{2}{6} \) = \( \frac{2 x 2}{6 x 6} \) = \( \frac{4}{36} \) = \(\frac{1}{9}\)
What is 5b5 x 3b6?
| 8b6 | |
| 15b6 | |
| 15b11 | |
| 15b-1 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
5b5 x 3b6
(5 x 3)b(5 + 6)
15b11
A factor is a positive __________ that divides evenly into a given number.
integer |
|
fraction |
|
mixed number |
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improper fraction |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
What is \( 2 \)\( \sqrt{32} \) - \( 9 \)\( \sqrt{2} \)
| -7\( \sqrt{32} \) | |
| -7\( \sqrt{64} \) | |
| -1\( \sqrt{2} \) | |
| -7\( \sqrt{2} \) |
To subtract these radicals together their radicands must be the same:
2\( \sqrt{32} \) - 9\( \sqrt{2} \)
2\( \sqrt{16 \times 2} \) - 9\( \sqrt{2} \)
2\( \sqrt{4^2 \times 2} \) - 9\( \sqrt{2} \)
(2)(4)\( \sqrt{2} \) - 9\( \sqrt{2} \)
8\( \sqrt{2} \) - 9\( \sqrt{2} \)
Now that the radicands are identical, you can subtract them:
8\( \sqrt{2} \) - 9\( \sqrt{2} \)Convert a-3 to remove the negative exponent.
| \( \frac{-1}{a^{-3}} \) | |
| \( \frac{-3}{-a} \) | |
| \( \frac{1}{a^3} \) | |
| \( \frac{-3}{a} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.