Your Results | Global Average | |
---|---|---|
Questions | 5 | 5 |
Correct | 0 | 2.53 |
Score | 0% | 51% |
What is \( 8 \)\( \sqrt{20} \) + \( 6 \)\( \sqrt{5} \)
14\( \sqrt{5} \) | |
48\( \sqrt{100} \) | |
48\( \sqrt{4} \) | |
22\( \sqrt{5} \) |
To add these radicals together their radicands must be the same:
8\( \sqrt{20} \) + 6\( \sqrt{5} \)
8\( \sqrt{4 \times 5} \) + 6\( \sqrt{5} \)
8\( \sqrt{2^2 \times 5} \) + 6\( \sqrt{5} \)
(8)(2)\( \sqrt{5} \) + 6\( \sqrt{5} \)
16\( \sqrt{5} \) + 6\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
16\( \sqrt{5} \) + 6\( \sqrt{5} \)What is 9\( \sqrt{9} \) x 8\( \sqrt{3} \)?
17\( \sqrt{9} \) | |
17\( \sqrt{27} \) | |
72\( \sqrt{3} \) | |
216\( \sqrt{3} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
9\( \sqrt{9} \) x 8\( \sqrt{3} \)
(9 x 8)\( \sqrt{9 \times 3} \)
72\( \sqrt{27} \)
Now we need to simplify the radical:
72\( \sqrt{27} \)
72\( \sqrt{3 \times 9} \)
72\( \sqrt{3 \times 3^2} \)
(72)(3)\( \sqrt{3} \)
216\( \sqrt{3} \)
What is \( \frac{2}{2} \) + \( \frac{6}{10} \)?
1 \( \frac{8}{10} \) | |
1\(\frac{3}{5}\) | |
1 \( \frac{5}{10} \) | |
\( \frac{7}{13} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [10, 20, 30, 40, 50] making 10 the smallest multiple 2 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 5}{2 x 5} \) + \( \frac{6 x 1}{10 x 1} \)
\( \frac{10}{10} \) + \( \frac{6}{10} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{10 + 6}{10} \) = \( \frac{16}{10} \) = 1\(\frac{3}{5}\)
Convert a-4 to remove the negative exponent.
\( \frac{1}{a^4} \) | |
\( \frac{-1}{-4a^{4}} \) | |
\( \frac{4}{a} \) | |
\( \frac{-1}{-4a} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
A machine in a factory has an error rate of 9 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 3 hours for maintenance.
How many error-free parts did the machine produce yesterday?
114.7 | |
88.4 | |
126.4 | |
100.8 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{9}{100} \) x 6 = \( \frac{9 \times 6}{100} \) = \( \frac{54}{100} \) = 0.54 errors per hour
So, in an average hour, the machine will produce 6 - 0.54 = 5.46 error free parts.
The machine ran for 24 - 3 = 21 hours yesterday so you would expect that 21 x 5.46 = 114.7 error free parts were produced yesterday.