ASVAB Arithmetic Reasoning Practice Test 382297 Results

Your Results Global Average
Questions 5 5
Correct 0 3.25
Score 0% 65%

Review

1

Solve 4 + (3 + 5) ÷ 3 x 3 - 42

53% Answer Correctly
\(\frac{2}{3}\)
4\(\frac{1}{2}\)
2
-4

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (3 + 5) ÷ 3 x 3 - 42
P: 4 + (8) ÷ 3 x 3 - 42
E: 4 + 8 ÷ 3 x 3 - 16
MD: 4 + \( \frac{8}{3} \) x 3 - 16
MD: 4 + \( \frac{24}{3} \) - 16
AS: \( \frac{12}{3} \) + \( \frac{24}{3} \) - 16
AS: \( \frac{36}{3} \) - 16
AS: \( \frac{36 - 48}{3} \)
\( \frac{-12}{3} \)
-4


2

Ezra loaned Damon $1,000 at an annual interest rate of 3%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$84
$66
$11
$30

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,000
i = 0.03 x $1,000
i = $30


3

Which of the following is not a prime number?

65% Answer Correctly

9

2

7

5


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


4

What is (y3)3?

80% Answer Correctly
y0
y6
3y3
y9

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(y3)3
y(3 * 3)
y9


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for division

commutative property for multiplication

commutative property for division

distributive property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).