To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 48 are [1, 2, 3, 4, 6, 8, 12, 16, 24, 48]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{28}{48} \) = \( \frac{\frac{28}{4}}{\frac{48}{4}} \) = \( \frac{7}{12} \)

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{10 + 4 + 9 + 5}{4} \) = \( \frac{28}{4} \) = 7

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{7b^9}{8b^3} \)
\( \frac{7}{8} \) b^{(9 - 3)}
\(\frac{7}{8}\)b⁶

A number in scientific notation has the format 0.000 x 10^exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

3,896,000 in scientific notation is 3.896 x 10⁶

To multiply terms with radicals, multiply the coefficients and radicands separately:

2\( \sqrt{3} \) x 6\( \sqrt{6} \)
(2 x 6)\( \sqrt{3 \times 6} \)
12\( \sqrt{18} \)

Now we need to simplify the radical:

12\( \sqrt{18} \)
12\( \sqrt{2 \times 9} \)
12\( \sqrt{2 \times 3^2} \)
(12)(3)\( \sqrt{2} \)
36\( \sqrt{2} \)