| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.03 |
| Score | 0% | 61% |
What is (y2)4?
| y-2 | |
| y8 | |
| 2y4 | |
| y2 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(y2)4The __________ is the greatest factor that divides two integers.
absolute value |
|
greatest common factor |
|
least common multiple |
|
greatest common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
If a mayor is elected with 88% of the votes cast and 71% of a town's 29,000 voters cast a vote, how many votes did the mayor receive?
| 11,530 | |
| 18,119 | |
| 14,825 | |
| 17,296 |
If 71% of the town's 29,000 voters cast ballots the number of votes cast is:
(\( \frac{71}{100} \)) x 29,000 = \( \frac{2,059,000}{100} \) = 20,590
The mayor got 88% of the votes cast which is:
(\( \frac{88}{100} \)) x 20,590 = \( \frac{1,811,920}{100} \) = 18,119 votes.
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 9 to 2 and the ratio of baseball to basketball cards is 9 to 1, what is the ratio of football to basketball cards?
| 81:2 | |
| 3:6 | |
| 7:6 | |
| 7:8 |
The ratio of football cards to baseball cards is 9:2 and the ratio of baseball cards to basketball cards is 9:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 81:18 and the ratio of baseball cards to basketball cards as 18:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 81:18, 18:2 which reduces to 81:2.
How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 15 gallon tank to fill it exactly halfway?
| 4 | |
| 6 | |
| 3 | |
| 8 |
To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{7\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 3