ASVAB Arithmetic Reasoning Practice Test 386480 Results

Your Results Global Average
Questions 5 5
Correct 0 3.48
Score 0% 70%

Review

1

What is \( \frac{40\sqrt{63}}{8\sqrt{9}} \)?

71% Answer Correctly
7 \( \sqrt{5} \)
\(\frac{1}{7}\) \( \sqrt{5} \)
5 \( \sqrt{7} \)
7 \( \sqrt{\frac{1}{5}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{40\sqrt{63}}{8\sqrt{9}} \)
\( \frac{40}{8} \) \( \sqrt{\frac{63}{9}} \)
5 \( \sqrt{7} \)


2

If \( \left|a - 7\right| \) - 2 = -1, which of these is a possible value for a?

62% Answer Correctly
5
8
1
-5

Solution

First, solve for \( \left|a - 7\right| \):

\( \left|a - 7\right| \) - 2 = -1
\( \left|a - 7\right| \) = -1 + 2
\( \left|a - 7\right| \) = 1

The value inside the absolute value brackets can be either positive or negative so (a - 7) must equal + 1 or -1 for \( \left|a - 7\right| \) to equal 1:

a - 7 = 1
a = 1 + 7
a = 8
a - 7 = -1
a = -1 + 7
a = 6

So, a = 6 or a = 8.


3

What is \( \frac{7z^6}{5z^4} \)?

60% Answer Correctly
1\(\frac{2}{5}\)z-2
1\(\frac{2}{5}\)z2
\(\frac{5}{7}\)z10
\(\frac{5}{7}\)z-2

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{7z^6}{5z^4} \)
\( \frac{7}{5} \) z(6 - 4)
1\(\frac{2}{5}\)z2


4

Roger loaned Monty $700 at an annual interest rate of 2%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$14
$66
$45
$7

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $700
i = 0.02 x $700
i = $14


5

How many 12-passenger vans will it take to drive all 53 members of the football team to an away game?

81% Answer Correctly
9 vans
14 vans
4 vans
5 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{53}{12} \) = 4\(\frac{5}{12}\)

So, it will take 4 full vans and one partially full van to transport the entire team making a total of 5 vans.