First, solve for \( \left|b + 2\right| \):

\( \left|b + 2\right| \) + 4 = 6
\( \left|b + 2\right| \) = 6 - 4
\( \left|b + 2\right| \) = 2

The value inside the absolute value brackets can be either positive or negative so (b + 2) must equal + 2 or -2 for \( \left|b + 2\right| \) to equal 2:

So, b = -4 or b = 0.

If the tiger has consumed 18 pounds of food in 3 days that's \( \frac{18}{3} \) = 6 pounds of food per day. The tiger needs to consume 60 - 18 = 42 more pounds of food to reach 60 pounds total. At 6 pounds of food per day that's \( \frac{42}{6} \) = 7 more days.

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.

The ratio of football cards to baseball cards is 9:2 and the ratio of baseball cards to basketball cards is 9:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 81:18 and the ratio of baseball cards to basketball cards as 18:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 81:18, 18:2 which reduces to 81:2.

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-6a^7}{5a^2} \)
\( \frac{-6}{5} \) a^{(7 - 2)}
-1\(\frac{1}{5}\)a⁵