To add these radicals together their radicands must be the same:

2\( \sqrt{18} \) + 6\( \sqrt{2} \)
2\( \sqrt{9 \times 2} \) + 6\( \sqrt{2} \)
2\( \sqrt{3^2 \times 2} \) + 6\( \sqrt{2} \)
(2)(3)\( \sqrt{2} \) + 6\( \sqrt{2} \)
6\( \sqrt{2} \) + 6\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (2 + 3) ÷ 5 x 3 - 2²
P: 2 + (5) ÷ 5 x 3 - 2²
E: 2 + 5 ÷ 5 x 3 - 4
MD: 2 + \( \frac{5}{5} \) x 3 - 4
MD: 2 + \( \frac{15}{5} \) - 4
AS: \( \frac{10}{5} \) + \( \frac{15}{5} \) - 4
AS: \( \frac{25}{5} \) - 4
AS: \( \frac{25 - 20}{5} \)
\( \frac{5}{5} \)
1

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $900
i = 0.05 x $900

No payments were made so the total amount due is the original amount + the accumulated interest:

The amount of flour you need is (2 - \(\frac{3}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{16}{8} \) - \( \frac{6}{8} \)) cups
\( \frac{10}{8} \) cups
1\(\frac{1}{4}\) cups

A number with an exponent (b^e) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b¹ = b) and a base with an exponent of 0 equals 1 ( (b⁰ = 1).