ASVAB Arithmetic Reasoning Practice Test 391555 Results

Your Results Global Average
Questions 5 5
Correct 0 3.84
Score 0% 77%

Review

1

A triathlon course includes a 400m swim, a 20.6km bike ride, and a 11.2km run. What is the total length of the race course?

69% Answer Correctly
40.2km
59.3km
32.2km
47.8km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 400 meters to kilometers, divide the distance by 1000 to get 0.4km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.4km + 20.6km + 11.2km
total distance = 32.2km


2

If a car travels 90 miles in 3 hours, what is the average speed?

86% Answer Correctly
30 mph
60 mph
20 mph
25 mph

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)
speed = \( \frac{90mi}{3h} \)
30 mph


3

A bread recipe calls for 1\(\frac{7}{8}\) cups of flour. If you only have 1\(\frac{5}{8}\) cups, how much more flour is needed?

62% Answer Correctly
2\(\frac{3}{8}\) cups
1\(\frac{3}{8}\) cups
\(\frac{1}{4}\) cups
2\(\frac{5}{8}\) cups

Solution

The amount of flour you need is (1\(\frac{7}{8}\) - 1\(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{15}{8} \) - \( \frac{13}{8} \)) cups
\( \frac{2}{8} \) cups
\(\frac{1}{4}\) cups


4

4! = ?

84% Answer Correctly

4 x 3

3 x 2 x 1

4 x 3 x 2 x 1

5 x 4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


5

Which of the following is a mixed number?

82% Answer Correctly

\({a \over 5} \)

\({7 \over 5} \)

\(1 {2 \over 5} \)

\({5 \over 7} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.