| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.82 |
| Score | 0% | 56% |
What is \( \frac{8x^9}{6x^3} \)?
| 1\(\frac{1}{3}\)x12 | |
| 1\(\frac{1}{3}\)x6 | |
| 1\(\frac{1}{3}\)x3 | |
| \(\frac{3}{4}\)x6 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{8x^9}{6x^3} \)
\( \frac{8}{6} \) x(9 - 3)
1\(\frac{1}{3}\)x6
A machine in a factory has an error rate of 2 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 2 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 129.4 | |
| 166.6 | |
| 126.7 | |
| 110.4 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{2}{100} \) x 6 = \( \frac{2 \times 6}{100} \) = \( \frac{12}{100} \) = 0.12 errors per hour
So, in an average hour, the machine will produce 6 - 0.12 = 5.88 error free parts.
The machine ran for 24 - 2 = 22 hours yesterday so you would expect that 22 x 5.88 = 129.4 error free parts were produced yesterday.
Which of the following statements about exponents is false?
b0 = 1 |
|
b1 = b |
|
b1 = 1 |
|
all of these are false |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
If there were a total of 250 raffle tickets sold and you bought 12 tickets, what's the probability that you'll win the raffle?
| 16% | |
| 2% | |
| 10% | |
| 5% |
You have 12 out of the total of 250 raffle tickets sold so you have a (\( \frac{12}{250} \)) x 100 = \( \frac{12 \times 100}{250} \) = \( \frac{1200}{250} \) = 5% chance to win the raffle.
What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?
| 61 | |
| 55 | |
| 58 | |
| 52 |
The equation for this sequence is:
an = an-1 + 4(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61