| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.51 |
| Score | 0% | 50% |
How many 2 gallon cans worth of fuel would you need to pour into an empty 8 gallon tank to fill it exactly halfway?
| 2 | |
| 2 | |
| 4 | |
| 6 |
To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{4 \text{ gallons}}{2 \text{ gallons}} \) = 2
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 9 to 2 and the ratio of baseball to basketball cards is 9 to 1, what is the ratio of football to basketball cards?
| 7:4 | |
| 5:1 | |
| 81:2 | |
| 9:1 |
The ratio of football cards to baseball cards is 9:2 and the ratio of baseball cards to basketball cards is 9:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 81:18 and the ratio of baseball cards to basketball cards as 18:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 81:18, 18:2 which reduces to 81:2.
What is \( 8 \)\( \sqrt{32} \) + \( 2 \)\( \sqrt{2} \)
| 16\( \sqrt{64} \) | |
| 10\( \sqrt{16} \) | |
| 16\( \sqrt{2} \) | |
| 34\( \sqrt{2} \) |
To add these radicals together their radicands must be the same:
8\( \sqrt{32} \) + 2\( \sqrt{2} \)
8\( \sqrt{16 \times 2} \) + 2\( \sqrt{2} \)
8\( \sqrt{4^2 \times 2} \) + 2\( \sqrt{2} \)
(8)(4)\( \sqrt{2} \) + 2\( \sqrt{2} \)
32\( \sqrt{2} \) + 2\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
32\( \sqrt{2} \) + 2\( \sqrt{2} \)What is 8\( \sqrt{7} \) x 4\( \sqrt{5} \)?
| 12\( \sqrt{5} \) | |
| 32\( \sqrt{12} \) | |
| 32\( \sqrt{35} \) | |
| 32\( \sqrt{7} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
8\( \sqrt{7} \) x 4\( \sqrt{5} \)
(8 x 4)\( \sqrt{7 \times 5} \)
32\( \sqrt{35} \)
What is \( \frac{42\sqrt{10}}{6\sqrt{5}} \)?
| \(\frac{1}{2}\) \( \sqrt{7} \) | |
| 2 \( \sqrt{\frac{1}{7}} \) | |
| 7 \( \sqrt{2} \) | |
| 7 \( \sqrt{\frac{1}{2}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{42\sqrt{10}}{6\sqrt{5}} \)
\( \frac{42}{6} \) \( \sqrt{\frac{10}{5}} \)
7 \( \sqrt{2} \)