ASVAB Arithmetic Reasoning Practice Test 396809 Results

Your Results Global Average
Questions 5 5
Correct 0 2.98
Score 0% 60%

Review

1

A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 3 to 2 and the ratio of baseball to basketball cards is 3 to 1, what is the ratio of football to basketball cards?

53% Answer Correctly
9:2
3:1
3:4
7:8

Solution

The ratio of football cards to baseball cards is 3:2 and the ratio of baseball cards to basketball cards is 3:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 9:6 and the ratio of baseball cards to basketball cards as 6:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 9:6, 6:2 which reduces to 9:2.


2

Find the average of the following numbers: 11, 7, 12, 6.

74% Answer Correctly
13
9
11
10

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{11 + 7 + 12 + 6}{4} \) = \( \frac{36}{4} \) = 9


3

If a mayor is elected with 80% of the votes cast and 35% of a town's 22,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
5,390
4,774
6,160
6,314

Solution

If 35% of the town's 22,000 voters cast ballots the number of votes cast is:

(\( \frac{35}{100} \)) x 22,000 = \( \frac{770,000}{100} \) = 7,700

The mayor got 80% of the votes cast which is:

(\( \frac{80}{100} \)) x 7,700 = \( \frac{616,000}{100} \) = 6,160 votes.


4

Solve 4 + (3 + 4) ÷ 5 x 2 - 32

52% Answer Correctly
\(\frac{5}{6}\)
\(\frac{3}{7}\)
\(\frac{5}{9}\)
-2\(\frac{1}{5}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (3 + 4) ÷ 5 x 2 - 32
P: 4 + (7) ÷ 5 x 2 - 32
E: 4 + 7 ÷ 5 x 2 - 9
MD: 4 + \( \frac{7}{5} \) x 2 - 9
MD: 4 + \( \frac{14}{5} \) - 9
AS: \( \frac{20}{5} \) + \( \frac{14}{5} \) - 9
AS: \( \frac{34}{5} \) - 9
AS: \( \frac{34 - 45}{5} \)
\( \frac{-11}{5} \)
-2\(\frac{1}{5}\)


5

A triathlon course includes a 200m swim, a 30.3km bike ride, and a 8.8km run. What is the total length of the race course?

69% Answer Correctly
56.6km
42.9km
39.3km
41.1km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.2km + 30.3km + 8.8km
total distance = 39.3km