| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
What is \( \frac{4a^8}{5a^3} \)?
| 1\(\frac{1}{4}\)a-5 | |
| \(\frac{4}{5}\)a5 | |
| 1\(\frac{1}{4}\)a11 | |
| 1\(\frac{1}{4}\)a5 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{4a^8}{5a^3} \)
\( \frac{4}{5} \) a(8 - 3)
\(\frac{4}{5}\)a5
What is \( \sqrt{\frac{25}{4}} \)?
| 2\(\frac{1}{2}\) | |
| 1 | |
| 2 | |
| \(\frac{1}{4}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{25}{4}} \)
\( \frac{\sqrt{25}}{\sqrt{4}} \)
\( \frac{\sqrt{5^2}}{\sqrt{2^2}} \)
\( \frac{5}{2} \)
2\(\frac{1}{2}\)
What is \( 7 \)\( \sqrt{125} \) - \( 3 \)\( \sqrt{5} \)
| 4\( \sqrt{0} \) | |
| 32\( \sqrt{5} \) | |
| 4\( \sqrt{5} \) | |
| 21\( \sqrt{125} \) |
To subtract these radicals together their radicands must be the same:
7\( \sqrt{125} \) - 3\( \sqrt{5} \)
7\( \sqrt{25 \times 5} \) - 3\( \sqrt{5} \)
7\( \sqrt{5^2 \times 5} \) - 3\( \sqrt{5} \)
(7)(5)\( \sqrt{5} \) - 3\( \sqrt{5} \)
35\( \sqrt{5} \) - 3\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
35\( \sqrt{5} \) - 3\( \sqrt{5} \)Find the average of the following numbers: 18, 12, 19, 11.
| 15 | |
| 13 | |
| 16 | |
| 12 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{18 + 12 + 19 + 11}{4} \) = \( \frac{60}{4} \) = 15
What is (b5)4?
| b20 | |
| b9 | |
| 4b5 | |
| b |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b5)4