ASVAB Arithmetic Reasoning Practice Test 396841 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

What is \( \frac{4a^8}{5a^3} \)?

60% Answer Correctly
1\(\frac{1}{4}\)a-5
\(\frac{4}{5}\)a5
1\(\frac{1}{4}\)a11
1\(\frac{1}{4}\)a5

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{4a^8}{5a^3} \)
\( \frac{4}{5} \) a(8 - 3)
\(\frac{4}{5}\)a5


2

What is \( \sqrt{\frac{25}{4}} \)?

70% Answer Correctly
2\(\frac{1}{2}\)
1
2
\(\frac{1}{4}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{25}{4}} \)
\( \frac{\sqrt{25}}{\sqrt{4}} \)
\( \frac{\sqrt{5^2}}{\sqrt{2^2}} \)
\( \frac{5}{2} \)
2\(\frac{1}{2}\)


3

What is \( 7 \)\( \sqrt{125} \) - \( 3 \)\( \sqrt{5} \)

38% Answer Correctly
4\( \sqrt{0} \)
32\( \sqrt{5} \)
4\( \sqrt{5} \)
21\( \sqrt{125} \)

Solution

To subtract these radicals together their radicands must be the same:

7\( \sqrt{125} \) - 3\( \sqrt{5} \)
7\( \sqrt{25 \times 5} \) - 3\( \sqrt{5} \)
7\( \sqrt{5^2 \times 5} \) - 3\( \sqrt{5} \)
(7)(5)\( \sqrt{5} \) - 3\( \sqrt{5} \)
35\( \sqrt{5} \) - 3\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

35\( \sqrt{5} \) - 3\( \sqrt{5} \)
(35 - 3)\( \sqrt{5} \)
32\( \sqrt{5} \)


4

Find the average of the following numbers: 18, 12, 19, 11.

74% Answer Correctly
15
13
16
12

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{18 + 12 + 19 + 11}{4} \) = \( \frac{60}{4} \) = 15


5

What is (b5)4?

80% Answer Correctly
b20
b9
4b5
b

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(b5)4
b(5 * 4)
b20