| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.36 |
| Score | 0% | 67% |
4! = ?
4 x 3 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
Solve for \( \frac{3!}{5!} \)
| 42 | |
| \( \frac{1}{20} \) | |
| 5 | |
| 4 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)
What is \( 4 \)\( \sqrt{12} \) + \( 5 \)\( \sqrt{3} \)
| 9\( \sqrt{36} \) | |
| 13\( \sqrt{3} \) | |
| 9\( \sqrt{4} \) | |
| 9\( \sqrt{12} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{12} \) + 5\( \sqrt{3} \)
4\( \sqrt{4 \times 3} \) + 5\( \sqrt{3} \)
4\( \sqrt{2^2 \times 3} \) + 5\( \sqrt{3} \)
(4)(2)\( \sqrt{3} \) + 5\( \sqrt{3} \)
8\( \sqrt{3} \) + 5\( \sqrt{3} \)
Now that the radicands are identical, you can add them together:
8\( \sqrt{3} \) + 5\( \sqrt{3} \)Which of the following is not an integer?
\({1 \over 2}\) |
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0 |
|
1 |
|
-1 |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
What is \( \sqrt{\frac{64}{9}} \)?
| \(\frac{1}{3}\) | |
| \(\frac{7}{8}\) | |
| 2\(\frac{2}{3}\) | |
| 2\(\frac{1}{4}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{64}{9}} \)
\( \frac{\sqrt{64}}{\sqrt{9}} \)
\( \frac{\sqrt{8^2}}{\sqrt{3^2}} \)
\( \frac{8}{3} \)
2\(\frac{2}{3}\)