| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.36 |
| Score | 0% | 67% |
A triathlon course includes a 200m swim, a 20.5km bike ride, and a 9.0km run. What is the total length of the race course?
| 29.8km | |
| 49.2km | |
| 37.6km | |
| 29.7km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.2km + 20.5km + 9.0km
total distance = 29.7km
What is the distance in miles of a trip that takes 1 hour at an average speed of 65 miles per hour?
| 270 miles | |
| 245 miles | |
| 65 miles | |
| 315 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 65mph \times 1h \)
65 miles
In a class of 27 students, 10 are taking German and 5 are taking Spanish. Of the students studying German or Spanish, 3 are taking both courses. How many students are not enrolled in either course?
| 24 | |
| 14 | |
| 15 | |
| 16 |
The number of students taking German or Spanish is 10 + 5 = 15. Of that group of 15, 3 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 15 - 3 = 12 who are taking at least one language. 27 - 12 = 15 students who are not taking either language.
How many 2 gallon cans worth of fuel would you need to pour into an empty 8 gallon tank to fill it exactly halfway?
| 4 | |
| 3 | |
| 2 | |
| 2 |
To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{4 \text{ gallons}}{2 \text{ gallons}} \) = 2
Solve for \( \frac{4!}{6!} \)
| 56 | |
| \( \frac{1}{30} \) | |
| \( \frac{1}{1680} \) | |
| \( \frac{1}{3024} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{6!} \)
\( \frac{4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5} \)
\( \frac{1}{30} \)