| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.06 |
| Score | 0% | 61% |
What is \( \frac{9}{6} \) - \( \frac{9}{14} \)?
| 2 \( \frac{6}{42} \) | |
| 2 \( \frac{3}{11} \) | |
| \( \frac{9}{42} \) | |
| \(\frac{6}{7}\) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 14 are [14, 28, 42, 56, 70, 84, 98]. The first few multiples they share are [42, 84] making 42 the smallest multiple 6 and 14 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{9 x 7}{6 x 7} \) - \( \frac{9 x 3}{14 x 3} \)
\( \frac{63}{42} \) - \( \frac{27}{42} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{63 - 27}{42} \) = \( \frac{36}{42} \) = \(\frac{6}{7}\)
What is 9\( \sqrt{5} \) x 3\( \sqrt{9} \)?
| 27\( \sqrt{5} \) | |
| 81\( \sqrt{5} \) | |
| 12\( \sqrt{5} \) | |
| 27\( \sqrt{9} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
9\( \sqrt{5} \) x 3\( \sqrt{9} \)
(9 x 3)\( \sqrt{5 \times 9} \)
27\( \sqrt{45} \)
Now we need to simplify the radical:
27\( \sqrt{45} \)
27\( \sqrt{5 \times 9} \)
27\( \sqrt{5 \times 3^2} \)
(27)(3)\( \sqrt{5} \)
81\( \sqrt{5} \)
The total water usage for a city is 25,000 gallons each day. Of that total, 27% is for personal use and 62% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 10,000 | |
| 8,800 | |
| 6,300 | |
| 8,750 |
62% of the water consumption is industrial use and 27% is personal use so (62% - 27%) = 35% more water is used for industrial purposes. 25,000 gallons are consumed daily so industry consumes \( \frac{35}{100} \) x 25,000 gallons = 8,750 gallons.
What is \( \frac{9a^8}{2a^3} \)?
| 4\(\frac{1}{2}\)a11 | |
| 4\(\frac{1}{2}\)a5 | |
| \(\frac{2}{9}\)a-5 | |
| 4\(\frac{1}{2}\)a24 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{9a^8}{2a^3} \)
\( \frac{9}{2} \) a(8 - 3)
4\(\frac{1}{2}\)a5
What is the distance in miles of a trip that takes 5 hours at an average speed of 60 miles per hour?
| 150 miles | |
| 210 miles | |
| 440 miles | |
| 300 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 60mph \times 5h \)
300 miles