ASVAB Arithmetic Reasoning Practice Test 402145 Results

Your Results Global Average
Questions 5 5
Correct 0 3.09
Score 0% 62%

Review

1

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

greatest common multiple

absolute value

greatest common factor

least common multiple


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


2

How many hours does it take a car to travel 220 miles at an average speed of 55 miles per hour?

85% Answer Correctly
6 hours
3 hours
5 hours
4 hours

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for time:

time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{220mi}{55mph} \)
4 hours


3

What is \( \sqrt{\frac{49}{81}} \)?

70% Answer Correctly
\(\frac{7}{9}\)
1\(\frac{1}{2}\)
1
\(\frac{1}{3}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{81}} \)
\( \frac{\sqrt{49}}{\sqrt{81}} \)
\( \frac{\sqrt{7^2}}{\sqrt{9^2}} \)
\(\frac{7}{9}\)


4

What is \( 7 \)\( \sqrt{18} \) + \( 5 \)\( \sqrt{2} \)

35% Answer Correctly
35\( \sqrt{9} \)
26\( \sqrt{2} \)
12\( \sqrt{2} \)
35\( \sqrt{18} \)

Solution

To add these radicals together their radicands must be the same:

7\( \sqrt{18} \) + 5\( \sqrt{2} \)
7\( \sqrt{9 \times 2} \) + 5\( \sqrt{2} \)
7\( \sqrt{3^2 \times 2} \) + 5\( \sqrt{2} \)
(7)(3)\( \sqrt{2} \) + 5\( \sqrt{2} \)
21\( \sqrt{2} \) + 5\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

21\( \sqrt{2} \) + 5\( \sqrt{2} \)
(21 + 5)\( \sqrt{2} \)
26\( \sqrt{2} \)


5

How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 9 gallon tank to fill it exactly halfway?

52% Answer Correctly
8
7
2
3

Solution

To fill a 9 gallon tank exactly halfway you'll need 4\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:

cans = \( \frac{4\frac{1}{2} \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 3