| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.63 |
| Score | 0% | 53% |
Which of the following statements about exponents is false?
b1 = 1 |
|
b0 = 1 |
|
all of these are false |
|
b1 = b |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
Solve 2 + (3 + 3) ÷ 4 x 4 - 22
| 4 | |
| 1\(\frac{1}{8}\) | |
| 1 | |
| 1\(\frac{1}{7}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (3 + 3) ÷ 4 x 4 - 22
P: 2 + (6) ÷ 4 x 4 - 22
E: 2 + 6 ÷ 4 x 4 - 4
MD: 2 + \( \frac{6}{4} \) x 4 - 4
MD: 2 + \( \frac{24}{4} \) - 4
AS: \( \frac{8}{4} \) + \( \frac{24}{4} \) - 4
AS: \( \frac{32}{4} \) - 4
AS: \( \frac{32 - 16}{4} \)
\( \frac{16}{4} \)
4
| 3.2 | |
| 1.0 | |
| 1.8 | |
| 1 |
1
What is \( \frac{2}{6} \) - \( \frac{2}{8} \)?
| 2 \( \frac{4}{7} \) | |
| \(\frac{1}{12}\) | |
| 2 \( \frac{2}{11} \) | |
| 2 \( \frac{8}{24} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 6 and 8 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 4}{6 x 4} \) - \( \frac{2 x 3}{8 x 3} \)
\( \frac{8}{24} \) - \( \frac{6}{24} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{8 - 6}{24} \) = \( \frac{2}{24} \) = \(\frac{1}{12}\)
A circular logo is enlarged to fit the lid of a jar. The new diameter is 30% larger than the original. By what percentage has the area of the logo increased?
| 17\(\frac{1}{2}\)% | |
| 35% | |
| 30% | |
| 15% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 30% the radius (and, consequently, the total area) increases by \( \frac{30\text{%}}{2} \) = 15%